What is the integral of x^2+4e^x+C ?

The integral of x^2+4e^x+C is (x^3)/3+4e^x+Cx+C

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integral of x^2+4e^x+C

\int x^{2} + 4 e^{x} + C d x

\frac{x ^{3}}{3} + 4 e^{x} + C x + C

Solution steps

\int x^{2} + 4 e^{x} + C d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 4 e^{x} d x + \int C d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 4 e^{x} d x = 4 e^{x}

\int C d x = C x

= \frac{x ^{3}}{3} + 4 e^{x} + C x

Add a constant to the solution

= \frac{x ^{3}}{3} + 4 e^{x} + C x + C

\frac{\partial}{\partial x} (2 \cdot x^{3} \cdot y^{2})

\int_{0}^{1} cos (nπ x) d x

\frac{d}{d x} (ln (6 x^{4} - 9 x - 3))

y^{^{''}} + 8 y = 0

\frac{d}{d x} (arctan (9^{x}))

What is the integral of x^2+4e^x+C ?
The integral of x^2+4e^x+C is (x^3)/3+4e^x+Cx+C