What is (\partial)/(\partial x)(2*x^3*y^2) ?

The answer to (\partial)/(\partial x)(2*x^3*y^2) is 6x^2y^2

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(\partial)/(\partial x)(2x^3y^2)

\frac{\partial}{\partial x} (2 \cdot x^{3} \cdot y^{2})

6 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial x} (2 x^{3} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y^{2} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 y^{2} \cdot 3 x^{3 - 1}

Simplify

= 6 x^{2} y^{2}

\int_{0}^{1} cos (nπ x) d x

\frac{d}{d x} (ln (6 x^{4} - 9 x - 3))

y^{^{''}} + 8 y = 0

\frac{d}{d x} (arctan (9^{x}))

\frac{d x}{d t} + 2 t x^{3} + \frac{x}{t} = 0

What is (\partial)/(\partial x)(2*x^3*y^2) ?
The answer to (\partial)/(\partial x)(2*x^3*y^2) is 6x^2y^2