What is the derivative of e^x+cos(x) ?

The derivative of e^x+cos(x) is e^x-sin(x)

What is the first derivative of e^x+cos(x) ?

The first derivative of e^x+cos(x) is e^x-sin(x)

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\frac{d}{d x} (e^{x} + cos (x))

e^{x} - sin (x)

Solution steps

\frac{d}{d x} (e^{x} + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x)) = - sin (x)

= e^{x} - sin (x)

\frac{d}{d x} (10 lo g_{10} (100 x))

\frac{d}{d x} (cos (2 x^{2} - 3))

f (x) = \frac{x ^{2}}{2 + x}

x^{2} - 2 x, x + 4

y = x^{2} - 1, y = - x^{2} + 1

What is the derivative of e^x+cos(x) ?
The derivative of e^x+cos(x) is e^x-sin(x)
What is the first derivative of e^x+cos(x) ?
The first derivative of e^x+cos(x) is e^x-sin(x)