What is the derivative of cos(2x^2-3) ?

The derivative of cos(2x^2-3) is -sin(2x^2-3)*4x

What is the first derivative of cos(2x^2-3) ?

The first derivative of cos(2x^2-3) is -sin(2x^2-3)*4x

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\frac{d}{d x} (cos (2 x^{2} - 3))

- sin (2 x^{2} - 3) \cdot 4 x

Solution steps

\frac{d}{d x} (cos (2 x^{2} - 3))

Apply the chain rule:

- sin (2 x^{2} - 3) \frac{d}{d x} (2 x^{2} - 3)

= - sin (2 x^{2} - 3) \frac{d}{d x} (2 x^{2} - 3)

\frac{d}{d x} (2 x^{2} - 3) = 4 x

= - sin (2 x^{2} - 3) \cdot 4 x

f (x) = \frac{x ^{2}}{2 + x}

x^{2} - 2 x, x + 4

y = x^{2} - 1, y = - x^{2} + 1

sin (2 x) d x + cos (3 y) d y = 0

\frac{d}{d x} (\frac{4 - 3 x}{3 x ^{2} + x})

What is the derivative of cos(2x^2-3) ?
The derivative of cos(2x^2-3) is -sin(2x^2-3)*4x
What is the first derivative of cos(2x^2-3) ?
The first derivative of cos(2x^2-3) is -sin(2x^2-3)*4x