What is the derivative of f(x)=2xln(3x)-2x ?

The derivative of f(x)=2xln(3x)-2x is 2ln(3x)

What is the first derivative of f(x)=2xln(3x)-2x ?

The first derivative of f(x)=2xln(3x)-2x is 2ln(3x)

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derivative of

f (x) = 2 x ln (3 x) - 2 x

2 ln (3 x)

Solution steps

\frac{d}{d x} (2 x ln (3 x) - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x ln (3 x)) - \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x ln (3 x)) = 2 (ln (3 x) + 1)

\frac{d}{d x} (2 x) = 2

= 2 (ln (3 x) + 1) - 2

Simplify

2 (ln (3 x) + 1) - 2 : 2 ln (3 x)

= 2 ln (3 x)

\int (x - 1)^{2} x^{3} (2 - x) d x

x \to - \infty lim (\frac{4}{x} - 12)

\frac{d}{d x} (2 sec^{2} (x) \cdot tan (x))

x d x + (x^{2} y + 4 y) d y = 0

y^{^{'}} + 5 y = 2

What is the derivative of f(x)=2xln(3x)-2x ?
The derivative of f(x)=2xln(3x)-2x is 2ln(3x)
What is the first derivative of f(x)=2xln(3x)-2x ?
The first derivative of f(x)=2xln(3x)-2x is 2ln(3x)