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Popular >

y^'+5y=2

Solution

y^{^{'}} + 5 y = 2

Solution

y = - \frac{e ^{- 5 t - c_{1}}}{5} + \frac{2}{5}

Solution steps

y^{'} (t) + 5 y = 2

Solve separable ODE:

y = - \frac{e ^{- 5 t - c_{1}}}{5} + \frac{2}{5}

y = - \frac{e ^{- 5 t - c_{1}}}{5} + \frac{2}{5}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+5y=2 ?
The solution for y^'+5y=2 is y=-(e^{-5t-c_{1}})/5+2/5