What is (\partial)/(\partial x)(5xy-2x^2y) ?

The answer to (\partial)/(\partial x)(5xy-2x^2y) is 5y-4yx

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(\partial)/(\partial x)(5xy-2x^2y)

\frac{\partial}{\partial x} (5 x y - 2 x^{2} y)

5 y - 4 y x

Solution steps

\frac{\partial}{\partial x} (5 x y - 2 x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (5 x y) - \frac{\partial}{\partial x} (2 x^{2} y)

\frac{\partial}{\partial x} (5 x y) = 5 y

\frac{\partial}{\partial x} (2 x^{2} y) = 4 y x

= 5 y - 4 y x

\int \frac{1}{4 + x ^{2}} d x

f (x) = 2 x ln (3 x) - 2 x

\int (x - 1)^{2} x^{3} (2 - x) d x

x \to - \infty lim (\frac{4}{x} - 12)

\frac{d}{d x} (2 sec^{2} (x) \cdot tan (x))

What is (\partial)/(\partial x)(5xy-2x^2y) ?
The answer to (\partial)/(\partial x)(5xy-2x^2y) is 5y-4yx