What is the integral from-1 to 1 of 12^x ?

The integral from-1 to 1 of 12^x is (143)/(12ln(12))

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integral from-1 to 1 of 12^x

\int_{- 1}^{1} 1 2^{x} d x

\frac{143}{12 ln ( 12 )}

Decimal Notation

4.79561 \dots

Solution steps

\int_{- 1}^{1} 1 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{1 2 ^{x}}{ln ( 12 )}]_{- 1}^{1}

Compute the boundaries:

\frac{143}{12 ln ( 12 )}

= \frac{143}{12 ln ( 12 )}

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} - 1})

y^{^{''}} + (8) y = 0

h \to + 0 lim (\frac{( 2 ^{h} - 1 )}{h})

n = 0 \sum \infty 100

y^{^{''}} - 2 y^{^{'}} + y = x^{2}

What is the integral from-1 to 1 of 12^x ?
The integral from-1 to 1 of 12^x is (143)/(12ln(12))