What is (d^2)/(dx^2)(x/(x^2-1)) ?

The answer to (d^2)/(dx^2)(x/(x^2-1)) is -(2x(-x^2-3))/((x^2-1)^3)

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(d^2)/(dx^2)(x/(x^2-1))

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} - 1})

- \frac{2 x ( - x ^{2} - 3 )}{( x ^{2} - 1 ) ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} - 1})

\frac{d}{d x} (\frac{x}{x ^{2} - 1}) = \frac{- x ^{2} - 1}{( x ^{2} - 1 ) ^{2}}

= \frac{d}{d x} (\frac{- x ^{2} - 1}{( x ^{2} - 1 ) ^{2}})

\frac{d}{d x} (\frac{- x ^{2} - 1}{( x ^{2} - 1 ) ^{2}}) = - \frac{2 x ( - x ^{2} - 3 )}{( x ^{2} - 1 ) ^{3}}

= - \frac{2 x ( - x ^{2} - 3 )}{( x ^{2} - 1 ) ^{3}}

y^{^{''}} + (8) y = 0

h \to + 0 lim (\frac{( 2 ^{h} - 1 )}{h})

n = 0 \sum \infty 100

y^{^{''}} - 2 y^{^{'}} + y = x^{2}

\frac{\partial}{\partial x} (x^{3} - 5 x y)

What is (d^2)/(dx^2)(x/(x^2-1)) ?
The answer to (d^2)/(dx^2)(x/(x^2-1)) is -(2x(-x^2-3))/((x^2-1)^3)