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Popular >

y^'-xy^'=2xy

Solution

y^{^{'}} - x y^{^{'}} = 2 x y

Solution

y = \frac{e ^{2 - 2 x + c_{1}}}{1 - 2 x + x ^{2}}

Solution steps

y^{'} (x) - x y^{'} (x) = 2 x y

Solve separable ODE:

y = \frac{e ^{2 - 2 x + c_{1}}}{1 - 2 x + x ^{2}}

y = \frac{e ^{2 - 2 x + c_{1}}}{1 - 2 x + x ^{2}}

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\int \frac{y}{y + 6} d y

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\int 2 x (x^{2} - 1)^{2} d x

area x=20-5y^2,x=5y^2-20 area

x = 20 - 5 y^{2}, x = 5 y^{2} - 20

Frequently Asked Questions (FAQ)

What is the solution for y^'-xy^'=2xy ?
The solution for y^'-xy^'=2xy is y=(e^{2-2x+c_{1}})/(1-2x+x^2)