What is the first derivative of 5x-4 ?

The first derivative of 5x-4 is 5

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derivative of 5x-4

derivative of

5 x - 4

5

Solution steps

\frac{d}{d x} (5 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x) - \frac{d}{d x} (4)

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (4) = 0

= 5 - 0

Simplify

= 5

\int \frac{y}{y + 6} d y

\int 2 x (x^{2} - 1)^{2} d x

x = 20 - 5 y^{2}, x = 5 y^{2} - 20

x \to 3 lim (\frac{3}{9 - x ^{2}})

y = x 4 - x^{2}, (2, - 2)