What is the tangent of sqrt(x)(81.9) ?

The tangent of sqrt(x)(81.9) is y=(40.95)/(sqrt(a_{0))}x+(819sqrt(a_{0)})/(20)

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tangent of sqrt(x)(81.9)

tangent of

x (81.9)

y = \frac{40.95}{a _{0}} x + \frac{819 a _{0}}{20}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0} \cdot 81.9)

Find the slope of

y = x 81.9 : \frac{d y}{d x} = \frac{40.95}{x}

Compute the slope of

y = x 81.9

x = a_{0} : m = \frac{40.95}{a _{0}}

Find the line with slope m=

\frac{40.95}{a _{0}}

and passing through

(a_{0}, a_{0} 81.9) : y = \frac{40.95}{a _{0}} x + \frac{819 a _{0}}{20}

y = \frac{40.95}{a _{0}} x + \frac{819 a _{0}}{20}

(1 + x)^{2} y^{^{'}} + (1 + x) y = 1

\int \frac{1}{( x - 2 ) x + 2} d x

(t - \frac{3 π}{6}) sin (6 t)

\frac{d}{d x} (6 ln (cos (x)))

\frac{\partial}{\partial x} (e^{x y} sin (y))

What is the tangent of sqrt(x)(81.9) ?
The tangent of sqrt(x)(81.9) is y=(40.95)/(sqrt(a_{0))}x+(819sqrt(a_{0)})/(20)