What is the derivative of y=e^4x^2+18 ?

The derivative of y=e^4x^2+18 is 2e^4x

What is the first derivative of y=e^4x^2+18 ?

The first derivative of y=e^4x^2+18 is 2e^4x

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derivative of

y = e^{4} x^{2} + 18

2 e^{4} x

Solution steps

\frac{d}{d x} (e^{4} x^{2} + 18)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{4} x^{2}) + \frac{d}{d x} (18)

\frac{d}{d x} (e^{4} x^{2}) = 2 e^{4} x

\frac{d}{d x} (18) = 0

= 2 e^{4} x + 0

Simplify

= 2 e^{4} x

f (x) = (\frac{8 x + 7}{9 x ^{2} + 6})

y = cos (x), y = sin (x)

7 e^{x}, 7 x e^{x^{2}}, [0, 1]

\int (\frac{1}{2} x + 3)^{2} d x

n = 1 \sum \infty \frac{5}{2 ^{n - 1}}

What is the derivative of y=e^4x^2+18 ?
The derivative of y=e^4x^2+18 is 2e^4x
What is the first derivative of y=e^4x^2+18 ?
The first derivative of y=e^4x^2+18 is 2e^4x