What is area 7e^x,7xe^{x^2},[0,1] ?

The answer to area 7e^x,7xe^{x^2},[0,1] is 7(e-1)-(7(e-1))/2

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area 7e^x,7xe^{x^2},[0,1]

area

7 e^{x}, 7 x e^{x^{2}}, [0, 1]

7 (e - 1) - \frac{7 ( e - 1 )}{2}

Decimal Notation

6.01398 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} 7 e^{x} - 7 x e^{x^{2}} d x

Solve

\int_{0}^{1} 7 e^{x} - 7 x e^{x^{2}} d x : 7 (e - 1) - \frac{7 ( e - 1 )}{2}

The area is:

= 7 (e - 1) - \frac{7 ( e - 1 )}{2}

\int (\frac{1}{2} x + 3)^{2} d x

n = 1 \sum \infty \frac{5}{2 ^{n - 1}}

\frac{\partial}{\partial x} (\frac{x - z}{y + z})

\int_{- 2}^{5} ∣ x - 3 ∣ d x

\int x cos (π x) d x

What is area 7e^x,7xe^{x^2},[0,1] ?
The answer to area 7e^x,7xe^{x^2},[0,1] is 7(e-1)-(7(e-1))/2