What is the derivative of x-2-0.5sin(x) ?

The derivative of x-2-0.5sin(x) is -0.5cos(x)+1

What is the first derivative of x-2-0.5sin(x) ?

The first derivative of x-2-0.5sin(x) is -0.5cos(x)+1

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\frac{d}{d x} (x - 2 - 0.5 sin (x))

- 0.5 cos (x) + 1

Solution steps

\frac{d}{d x} (x - 2 - 0.5 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (2) - \frac{d}{d x} (0.5 sin (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

\frac{d}{d x} (0.5 sin (x)) = 0.5 cos (x)

= 1 - 0 - 0.5 cos (x)

Simplify

= - 0.5 cos (x) + 1

\frac{d}{d s} (s t)

f (x) = - 4 sin (x)

2 x + 5

x y^{^{'}} + (ln (x)) y = 0

\int \frac{x ^{2} - 4 x + 4}{x ^{2} - 4 x + 53} d x

What is the derivative of x-2-0.5sin(x) ?
The derivative of x-2-0.5sin(x) is -0.5cos(x)+1
What is the first derivative of x-2-0.5sin(x) ?
The first derivative of x-2-0.5sin(x) is -0.5cos(x)+1