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Popular >

xy^'+(ln(x))y=0

Solution

x y^{^{'}} + (ln (x)) y = 0

Solution

y = e^{- \frac{l n ^{2} ( x )}{2} + c_{1}}

Solution steps

x y^{'} (x) + (ln (x)) y = 0

Solve separable ODE:

y = e^{- \frac{l n ^{2} ( x )}{2} + c_{1}}

y = e^{- \frac{l n ^{2} ( x )}{2} + c_{1}}

Popular Examples

integral of (x^2-4x+4)/(sqrt(x^2-4x+53))

\int \frac{x ^{2} - 4 x + 4}{x ^{2} - 4 x + 53} d x

integral of-5e^x+4/x

\int - 5 e^{x} + \frac{4}{x} d x

derivative of (25/x+(100)/(15-x))

\frac{d}{d x} (\frac{25}{x} + \frac{100}{15 - x})

tangent of x^3-4x tangent of

x^{3} - 4 x

integral of x(a-x)^{5/2}

\int x (a - x)^{\frac{5}{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'+(ln(x))y=0 ?
The solution for xy^'+(ln(x))y=0 is y=e^{-(ln^2(x))/2+c_{1}}