What is the tangent of f(x)=3x^2,(1,3) ?

The tangent of f(x)=3x^2,(1,3) is y=6x-3

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tangent of f(x)=3x^2,(1,3)

tangent of

f (x) = 3 x^{2}, (1, 3)

y = 6 x - 3

Solution steps

Find the slope of

f (x) = 3 x^{2} : \frac{df ( x )}{d x} = 6 x

Compute the slope of

f (x) = 3 x^{2}

(1, 3) : m = 6

Find the line with slope m=

6

and passing through

(1, 3) : y = 6 x - 3

y = 6 x - 3

y^{^{'}} = \frac{e ^{x}}{y}

\int_{1}^{5} \frac{2}{x} d x

x \to 0 lim (\frac{20}{1 + x})

\int cos (5)

\int e^{x} \cdot \frac{1}{x} d x

What is the tangent of f(x)=3x^2,(1,3) ?
The tangent of f(x)=3x^2,(1,3) is y=6x-3