What is the solution for y^'=(e^x)/y ?

The solution for y^'=(e^x)/y is y=sqrt(2e^x+c_{1)},y=-sqrt(2e^x+c_{1)}

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y^'=(e^x)/y

y^{^{'}} = \frac{e ^{x}}{y}

y = 2 e^{x} + c_{1}, y = - 2 e^{x} + c_{1}

Solution steps

y^{'} (x) = \frac{e ^{x}}{y}

Solve separable ODE:

y = 2 e^{x} + c_{1}, y = - 2 e^{x} + c_{1}

y = 2 e^{x} + c_{1}, y = - 2 e^{x} + c_{1}

\int_{1}^{5} \frac{2}{x} d x

x \to 0 lim (\frac{20}{1 + x})

\int cos (5)

\int e^{x} \cdot \frac{1}{x} d x

y = cos (7 x)

What is the solution for y^'=(e^x)/y ?
The solution for y^'=(e^x)/y is y=sqrt(2e^x+c_{1)},y=-sqrt(2e^x+c_{1)}