What is the tangent of f(x)=3x-4x^2,(-3,-45) ?

The tangent of f(x)=3x-4x^2,(-3,-45) is y=27x+36

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tangent of f(x)=3x-4x^2,(-3,-45)

tangent

y = 27 x + 36

Solution steps

Find the slope of

f (x) = 3 x - 4 x^{2} : \frac{df ( x )}{d x} = 3 - 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 27

Find the line with slope m=

27

and passing through

(- 3, - 45) : y = 27 x + 36

y = 27 x + 36

What is the tangent of f(x)=3x-4x^2,(-3,-45) ?
The tangent of f(x)=3x-4x^2,(-3,-45) is y=27x+36