What is the solution for f^'(x)=sin(4)(4x^5) ?

The solution for f^'(x)=sin(4)(4x^5) is f(x)= 2/3 sin(4)x^6+c_{1}

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f^'(x)=sin(4)(4x^5)

f^{^{'}} (x) = sin (4) (4 x^{5})

f (x) = \frac{2}{3} sin (4) x^{6} + c_{1}

Solution steps

f^{'} (x) = sin (4) (4 x^{5})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int sin (4) \cdot 4 x^{5} d x

\int sin (4) \cdot 4 x^{5} d x = \frac{2}{3} sin (4) x^{6} + c_{1}

f (x) = \frac{2}{3} sin (4) x^{6} + c_{1}

9 (x - 4)^{\frac{2}{3}}

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What is the solution for f^'(x)=sin(4)(4x^5) ?
The solution for f^'(x)=sin(4)(4x^5) is f(x)= 2/3 sin(4)x^6+c_{1}