What is the tangent of f(x)=5sqrt(x),(25,25) ?

The tangent of f(x)=5sqrt(x),(25,25) is y= 1/2 x+25/2

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tangent of f(x)=5sqrt(x),(25,25)

tangent of

f (x) = 5 x, (25, 25)

y = \frac{1}{2} x + \frac{25}{2}

Solution steps

Find the slope of

f (x) = 5 x : \frac{df ( x )}{d x} = \frac{5}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(25, 25) : y = \frac{1}{2} x + \frac{25}{2}

y = \frac{1}{2} x + \frac{25}{2}

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} + 9 y = 0

y^{^{'}} + \frac{1}{165} y = 0.48

\frac{d}{d x} (10 sin (2 x) + 15 cos (2 x) + 100)

\frac{d}{d x} (arctan (\frac{x}{1 + 1 - x ^{2}}))

a re a y = 7 x, y = x^{2}

What is the tangent of f(x)=5sqrt(x),(25,25) ?
The tangent of f(x)=5sqrt(x),(25,25) is y= 1/2 x+25/2