What is the solution for y^'+1/165 y=0.48 ?

The solution for y^'+1/165 y=0.48 is y=-(e^{\frac{-t-c_{1})/(165)}}{0.00606…}+(0.48)/(0.00606…)

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y^'+1/165 y=0.48

y^{^{'}} + \frac{1}{165} y = 0.48

y = - \frac{e ^{\frac{- t - c _{1}}{165}}}{0.00606 \dots} + \frac{0.48}{0.00606 \dots}

Solution steps

y^{'} (t) + \frac{1}{165} y = 0.48

Solve separable ODE:

y = - \frac{e ^{\frac{- t - c _{1}}{165}}}{0.00606 \dots} + \frac{0.48}{0.00606 \dots}

y = - \frac{e ^{\frac{- t - c _{1}}{165}}}{0.00606 \dots} + \frac{0.48}{0.00606 \dots}

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What is the solution for y^'+1/165 y=0.48 ?
The solution for y^'+1/165 y=0.48 is y=-(e^{\frac{-t-c_{1})/(165)}}{0.00606…}+(0.48)/(0.00606…)