What is 1/((z-1)^3)*1/(e^{z+1)} ?

The solution to 1/((z-1)^3)*1/(e^{z+1)} is 1/(e^{z+1)(z-1)^3}

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simplify 1/((z-1)^3)*1/(e^{z+1)}

simplify

\frac{1}{( z - 1 ) ^{3}} \cdot \frac{1}{e ^{z + 1}}

\frac{1}{e ^{z + 1} ( z - 1 ) ^{3}}

Solution steps

\frac{1}{( z - 1 ) ^{3}} \cdot \frac{1}{e ^{z + 1}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{( z - 1 ) ^{3} e ^{z + 1}}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{e ^{z + 1} ( z - 1 ) ^{3}}

\frac{d y}{d x} = \frac{x ^{2} - 3 y ^{2}}{2 x y}

\frac{d}{d y} (y - \frac{y}{x ^{2}} e^{\frac{y}{x}})

5 sin (\frac{π}{4})

\frac{d}{d x} (\frac{y}{x - y})

f (x) = \frac{1}{3 + 2 x}, (2, \frac{1}{7})

What is 1/((z-1)^3)*1/(e^{z+1)} ?
The solution to 1/((z-1)^3)*1/(e^{z+1)} is 1/(e^{z+1)(z-1)^3}