What is the tangent of f(x)= 1/(3+2x),(2, 1/7) ?

The tangent of f(x)= 1/(3+2x),(2, 1/7) is y=-2/49 x+11/49

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 1/(3+2x),(2, 1/7)

tangent of

f (x) = \frac{1}{3 + 2 x}, (2, \frac{1}{7})

y = - \frac{2}{49} x + \frac{11}{49}

Solution steps

Find the slope of

f (x) = \frac{1}{3 + 2 x} : \frac{df ( x )}{d x} = - \frac{2}{( 3 + 2 x ) ^{2}}

Compute the slope of

f (x) = \frac{1}{3 + 2 x}

(2, \frac{1}{7}) : m = - \frac{2}{49}

Find the line with slope m=

- \frac{2}{49}

and passing through

(2, \frac{1}{7}) : y = - \frac{2}{49} x + \frac{11}{49}

y = - \frac{2}{49} x + \frac{11}{49}

\int 3 sin^{3} (x) cos^{5} (x) d x

\frac{8 x ^{2} + 6 x + 2}{x}

y = (arctan (4 x))^{2}

\int \frac{x - 2}{x ^{2}} d x

\frac{d}{d x} (x e^{x y})

What is the tangent of f(x)= 1/(3+2x),(2, 1/7) ?
The tangent of f(x)= 1/(3+2x),(2, 1/7) is y=-2/49 x+11/49