maclaurin 1/(2+3x)

Lösung

maclaurin

\frac{1}{2 + 3 x}

\frac{1}{2} - \frac{3}{4} x + \frac{9}{8} x^{2} - \frac{27}{16} x^{3} + \frac{81}{32} x^{4} + \dots

Schritte zur Lösung

Apply the Maclaurin Formula

= \frac{1}{2} + \frac{\frac{d}{d x} ( \frac{1}{2 + 3 x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{1}{2 + 3 x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{1}{2 + 3 x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= \frac{1}{2} + \frac{- \frac{3}{4}}{1 !} x + \frac{\frac{9}{4}}{2 !} x^{2} + \frac{- \frac{81}{8}}{3 !} x^{3} + \frac{\frac{243}{4}}{4 !} x^{4} + \dots

Fasse zusammen

= \frac{1}{2} - \frac{3}{4} x + \frac{9}{8} x^{2} - \frac{27}{16} x^{3} + \frac{81}{32} x^{4} + \dots

d er i v a t i v e f (x) = (x + 2 x) (2 x + 1)

\int \frac{( e ^{\frac{1}{x}} )}{x ^{3}} d x

\int - 2 x e^{- x^{2}} d x

\int_{1}^{4} \frac{x ^{2} + 7}{5 x - x ^{2}} d x

y^{^{'}} = e^{- y} (x^{2} - 6)