What is the solution for y^{''}-10y^'+34y=0 ?

The solution for y^{''}-10y^'+34y=0 is y=e^{5t}(c_{1}cos(3t)+c_{2}sin(3t))

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y^{''}-10y^'+34y=0

y^{^{''}} - 10 y^{^{'}} + 34 y = 0

y = e^{5 t} (c_{1} cos (3 t) + c_{2} sin (3 t))

Solution steps

y^{''} (t) - 10 y^{'} (t) + 34 y = 0

Solve linear ODE:

y = e^{5 t} (c_{1} cos (3 t) + c_{2} sin (3 t))

y = e^{5 t} (c_{1} cos (3 t) + c_{2} sin (3 t))

\frac{\partial}{\partial x} (x^{- \frac{1}{2}} cos (x))

\frac{s - 1}{s ( s ^{2} + s + 1 )}

\frac{\partial}{\partial x} (e^{e^{x y}})

x ∣ x - 2 ∣

x \to - 2 lim (2 ∣ x + 2 ∣)

What is the solution for y^{''}-10y^'+34y=0 ?
The solution for y^{''}-10y^'+34y=0 is y=e^{5t}(c_{1}cos(3t)+c_{2}sin(3t))