What is the tangent of y= 4/(1+x^2),(1,2) ?

The tangent of y= 4/(1+x^2),(1,2) is y=-2x+4

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tangent of y= 4/(1+x^2),(1,2)

tangent of

y = \frac{4}{1 + x ^{2}}, (1, 2)

y = - 2 x + 4

Solution steps

Find the slope of

y = \frac{4}{1 + x ^{2}} : \frac{d y}{d x} = - \frac{8 x}{( 1 + x ^{2} ) ^{2}}

Compute the slope of

y = \frac{4}{1 + x ^{2}}

(1, 2) : m = - 2

Find the line with slope m=

- 2

and passing through

(1, 2) : y = - 2 x + 4

y = - 2 x + 4

\int \frac{6 - 2 x}{9 - x ^{2}} d x

\int \frac{5 x - 6}{x ^{2} + 4} d x

\frac{\partial}{\partial x} (sin (7 x^{4} y - 7 x y^{4}))

y^{^{''}} - 10 y^{^{'}} + 34 y = 0

\frac{\partial}{\partial x} (x^{- \frac{1}{2}} cos (x))

What is the tangent of y= 4/(1+x^2),(1,2) ?
The tangent of y= 4/(1+x^2),(1,2) is y=-2x+4