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Popular >

integral from 0 to 4 of 4y-y^2

Solution

\int_{0}^{4} 4 y - y^{2} d y

Solution

\frac{32}{3}

+1

Solution steps

\int_{0}^{4} 4 y - y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 4 y d y - \int_{0}^{4} y^{2} d y

\int_{0}^{4} 4 y d y = 32

\int_{0}^{4} y^{2} d y = \frac{64}{3}

= 32 - \frac{64}{3}

Simplify

32 - \frac{64}{3} : \frac{32}{3}

= \frac{32}{3}

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of 4y-y^2 ?
The integral from 0 to 4 of 4y-y^2 is 32/3