What is the tangent of-3x^{1/2}+x^{3/2},\at x=9 ?

The tangent of-3x^{1/2}+x^{3/2},\at x=9 is y=4x-18

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tangent of-3x^{1/2}+x^{3/2},\at x=9

tangent

y = 4 x - 18

Solution steps

Find the tangent point:

(9, 18)

Find the slope of

y = - 3 x^{\frac{1}{2}} + x^{\frac{3}{2}} : \frac{d y}{d x} = - \frac{3}{2 x ^{\frac{1}{2}}} + \frac{3 x ^{\frac{1}{2}}}{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(9, 18) : y = 4 x - 18

y = 4 x - 18

What is the tangent of-3x^{1/2}+x^{3/2},\at x=9 ?
The tangent of-3x^{1/2}+x^{3/2},\at x=9 is y=4x-18