What is the tangent of-3x^{1/2}+x^{3/2},\at x=9 ?

The tangent of-3x^{1/2}+x^{3/2},\at x=9 is y=4x-18

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tangent of-3x^{1/2}+x^{3/2},\at x=9

tangent of

- 3 x^{\frac{1}{2}} + x^{\frac{3}{2}}, at x = 9

y = 4 x - 18

Solution steps

Find the tangent point:

(9, 18)

Find the slope of

y = - 3 x^{\frac{1}{2}} + x^{\frac{3}{2}} : \frac{d y}{d x} = - \frac{3}{2 x ^{\frac{1}{2}}} + \frac{3 x ^{\frac{1}{2}}}{2}

Compute the slope of

y = - 3 x^{\frac{1}{2}} + x^{\frac{3}{2}}

x = 9 : m = 4

Find the line with slope m=

4

and passing through

(9, 18) : y = 4 x - 18

y = 4 x - 18

\frac{d}{d x} ((\frac{x ^{2} + 2}{3})^{2})

(3, 2), (- 3, - 2)

A e^{x}

f (x) = sec (x) tan (x)

\frac{d}{d x} (- 4 cos (x) + sin (x))

What is the tangent of-3x^{1/2}+x^{3/2},\at x=9 ?
The tangent of-3x^{1/2}+x^{3/2},\at x=9 is y=4x-18