What is (d^2)/(dx^2)(-x/y) ?

The answer to (d^2)/(dx^2)(-x/y) is (x\frac{d^2y)/(dx^2)y+2(dy)/(dx)(-x(dy)/(dx)+y)}{y^3}

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(d^2)/(dx^2)(-x/y)

\frac{d ^{2}}{d x ^{2}} (- \frac{x}{y})

\frac{x \frac{d ^{2} y}{d x ^{2}} y + 2 \frac{d y}{d x} ( - x \frac{d y}{d x} + y )}{y ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (- \frac{x}{y})

\frac{d}{d x} (- \frac{x}{y}) = - \frac{y - x \frac{d y}{d x}}{y ^{2}}

= \frac{d}{d x} (- \frac{y - x \frac{d y}{d x}}{y ^{2}})

\frac{d}{d x} (- \frac{y - x \frac{d y}{d x}}{y ^{2}}) = \frac{x \frac{d ^{2} y}{d x ^{2}} y + 2 \frac{d y}{d x} ( - x \frac{d y}{d x} + y )}{y ^{3}}

= \frac{x \frac{d ^{2} y}{d x ^{2}} y + 2 \frac{d y}{d x} ( - x \frac{d y}{d x} + y )}{y ^{3}}

y^{^{''}} + 36 y = 6 t^{2}

5^{x^{3}}

\frac{( k ^{2} - x ^{2} ) ^{3}}{x ^{2} + a ^{2}}

\int sec (x) tan (x) 1 + sec (x) d x

What is (d^2)/(dx^2)(-x/y) ?
The answer to (d^2)/(dx^2)(-x/y) is (x\frac{d^2y)/(dx^2)y+2(dy)/(dx)(-x(dy)/(dx)+y)}{y^3}