y^{''}+36y=6t^2

Lösung

y^{^{''}} + 36 y = 6 t^{2}

y = c_{1} cos (6 t) + c_{2} sin (6 t) + \frac{t ^{2}}{6} - \frac{1}{108}

Schritte zur Lösung

y^{''} (t) + 36 y = 6 t^{2}

Solve linear ODE:

y = c_{1} cos (6 t) + c_{2} sin (6 t) + \frac{t ^{2}}{6} - \frac{1}{108}

y = c_{1} cos (6 t) + c_{2} sin (6 t) + \frac{t ^{2}}{6} - \frac{1}{108}

d er i v a t i v e 5^{x^{3}}

e x p an d \frac{( k ^{2} - x ^{2} ) ^{3}}{x ^{2} + a ^{2}}

\int 5 x 3 (9 - 4 x^{2})^{2} d x

\int sec (x) tan (x) 1 + sec (x) d x

f (x) = x ∣ x ∣