What is the integral of (4/(x^2)) ?

The integral of (4/(x^2)) is -4/x+C

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integral of (4/(x^2))

\int (\frac{4}{x ^{2}}) d x

- \frac{4}{x} + C

Solution steps

\int \frac{4}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= 4 (- \frac{1}{x})

Simplify

4 (- \frac{1}{x}) : - \frac{4}{x}

= - \frac{4}{x}

Add a constant to the solution

= - \frac{4}{x} + C

\frac{x d y}{d x} + 5 y = 7 x^{2}, f (2) = 5

\frac{d}{d x} (C x e^{- x})

\int - 16 cos (4 t + π) d t

\frac{d}{d x} ((x - 2)^{x + 1})

(y^{- 2})^{^{'}}