What is the integral of (-3)/((2x)^2) ?

The integral of (-3)/((2x)^2) is -3(1/(4x)-1/(2x))+C

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integral of (-3)/((2x)^2)

\int \frac{- 3}{( 2 x ) ^{2}} d x

- 3 (\frac{1}{4 x} - \frac{1}{2 x}) + C

Solution steps

\int \frac{- 3}{( 2 x ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int \frac{1}{( 2 x ) ^{2}} d x

Apply Integration By Parts

: \frac{1}{4 x} - \int - \frac{1}{2 x ^{2}} d x

= - 3 (\frac{1}{4 x} - \int - \frac{1}{2 x ^{2}} d x)

\int - \frac{1}{2 x ^{2}} d x = \frac{1}{2 x}

= - 3 (\frac{1}{4 x} - \frac{1}{2 x})

Add a constant to the solution

= - 3 (\frac{1}{4 x} - \frac{1}{2 x}) + C

x \to 2 lim (3 x + 2)

y = 6 x - x^{2}

\frac{d}{d x} ((2 e^{x} + x^{2}) ln (x))

x \to 1 lim (x)

\frac{1}{s ^{2}} - \frac{1}{s} + \frac{1}{( s - 2 )}

What is the integral of (-3)/((2x)^2) ?
The integral of (-3)/((2x)^2) is -3(1/(4x)-1/(2x))+C