What is the derivative of f(x)=(2x)/7+1 ?

The derivative of f(x)=(2x)/7+1 is 2/7

What is the first derivative of f(x)=(2x)/7+1 ?

The first derivative of f(x)=(2x)/7+1 is 2/7

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derivative of

f (x) = \frac{2 x}{7} + 1

\frac{2}{7}

Solution steps

\frac{d}{d x} (\frac{2 x}{7} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2 x}{7}) + \frac{d}{d x} (1)

\frac{d}{d x} (\frac{2 x}{7}) = \frac{2}{7}

\frac{d}{d x} (1) = 0

= \frac{2}{7} + 0

Simplify

= \frac{2}{7}

\frac{d y}{d x} = (x - 2) e^{- 2 y}

\frac{\partial}{\partial x} ((2 - x) (5 - x - 2 y))

x \to 2 lim (\frac{3 x + 4}{5 x + 7})

\frac{d}{d x} (\frac{1}{cos ( x )} + \frac{1}{sin ( x + 1 )})

What is the derivative of f(x)=(2x)/7+1 ?
The derivative of f(x)=(2x)/7+1 is 2/7
What is the first derivative of f(x)=(2x)/7+1 ?
The first derivative of f(x)=(2x)/7+1 is 2/7