What is the solution for (dy)/(dx)=(x-2)e^{-2y} ?

The solution for (dy)/(dx)=(x-2)e^{-2y} is y=(ln(x^2-4x+c_{1}))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(x-2)e^{-2y}

\frac{d y}{d x} = (x - 2) e^{- 2 y}

y = \frac{ln ( x ^{2} - 4 x + c _{1} )}{2}

Solution steps

\frac{d y}{d x} = (x - 2) e^{- 2 y}

Solve separable ODE:

y = \frac{ln ( x ^{2} - 4 x + c _{1} )}{2}

y = \frac{ln ( x ^{2} - 4 x + c _{1} )}{2}

\frac{\partial}{\partial x} ((2 - x) (5 - x - 2 y))

x \to 2 lim (\frac{3 x + 4}{5 x + 7})

\frac{d}{d x} (\frac{1}{cos ( x )} + \frac{1}{sin ( x + 1 )})

\frac{d}{d θ} (\frac{e ^{i θ} + e ^{- i θ}}{2})

y = \frac{t - t}{t ^{\frac{1}{3}}}

What is the solution for (dy)/(dx)=(x-2)e^{-2y} ?
The solution for (dy)/(dx)=(x-2)e^{-2y} is y=(ln(x^2-4x+c_{1}))/2