What is the integral of (cos(x))/(1+cos(x)) ?

The integral of (cos(x))/(1+cos(x)) is -csc(x)+cot(x)+x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (cos(x))/(1+cos(x))

\int \frac{cos ( x )}{1 + cos ( x )} d x

- csc (x) + cot (x) + x + C

Solution steps

\int \frac{cos ( x )}{1 + cos ( x )} d x

Multiply by the conjugate of

1 + cos (x) : \frac{sin ^{2} ( x )}{1 - cos ( x )}

= \int \frac{cos ( x )}{\frac{s i n ^{2} ( x )}{1 - c o s ( x )}} d x

Expand

\frac{cos ( x )}{\frac{s i n ^{2} ( x )}{1 - c o s ( x )}} : \frac{cos ( x )}{sin ^{2} ( x )} - \frac{cos ^{2} ( x )}{sin ^{2} ( x )}

= \int \frac{cos ( x )}{sin ^{2} ( x )} - \frac{cos ^{2} ( x )}{sin ^{2} ( x )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{cos ( x )}{sin ^{2} ( x )} d x - \int \frac{cos ^{2} ( x )}{sin ^{2} ( x )} d x

\int \frac{cos ( x )}{sin ^{2} ( x )} d x = - csc (x)

\int \frac{cos ^{2} ( x )}{sin ^{2} ( x )} d x = - cot (x) - x

= - csc (x) - (- cot (x) - x)

Simplify

= - csc (x) + cot (x) + x

Add a constant to the solution

= - csc (x) + cot (x) + x + C

\frac{d y}{d x} = \frac{1 - x ^{2}}{y ^{2}}

t + t^{3}

\frac{d y}{d x} = 8 - 4 y

\int \frac{e ^{2 x}}{3 x} d x

\frac{d}{d x} (x^{3} - 4 x + 7)

What is the integral of (cos(x))/(1+cos(x)) ?
The integral of (cos(x))/(1+cos(x)) is -csc(x)+cot(x)+x+C