What is the integral from-1 to 4 of (x^2+x^3) ?

The integral from-1 to 4 of (x^2+x^3) is 1025/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 4 of (x^2+x^3)

\int_{- 1}^{4} (x^{2} + x^{3}) d x

\frac{1025}{12}

Decimal Notation

85.41666 \dots

Solution steps

\int_{- 1}^{4} x^{2} + x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{4} x^{2} d x + \int_{- 1}^{4} x^{3} d x

\int_{- 1}^{4} x^{2} d x = \frac{65}{3}

\int_{- 1}^{4} x^{3} d x = \frac{255}{4}

= \frac{65}{3} + \frac{255}{4}

Simplify

\frac{65}{3} + \frac{255}{4} : \frac{1025}{12}

= \frac{1025}{12}

x^{3}

f (x) = \frac{1 - 3 ( a - 1 )}{8}

\frac{d}{d x} (\frac{2 x}{4 x ^{2} + 1})

\int \frac{cos ( x )}{1 + cos ( x )} d x

\frac{d y}{d x} = \frac{1 - x ^{2}}{y ^{2}}

What is the integral from-1 to 4 of (x^2+x^3) ?
The integral from-1 to 4 of (x^2+x^3) is 1025/12