What is (\partial)/(\partial x)(sin(2x)cos(2t)) ?

The answer to (\partial)/(\partial x)(sin(2x)cos(2t)) is cos(2t)cos(2x)*2

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(\partial)/(\partial x)(sin(2x)cos(2t))

\frac{\partial}{\partial x} (sin (2 x) cos (2 t))

cos (2 t) cos (2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x) cos (2 t))

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (2 t) \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= cos (2 t) cos (2 x) \cdot 2

\int \frac{ln ( 2 x )}{ln ( 4 x ) x} d x

\frac{d}{d x} ((x + 6)^{7} (x + 3)^{5})

y^{^{'}} = \frac{( x - 3 )}{( y - 4 )}

\int x^{2} - x - 2 d x

\frac{d}{d x} (\frac{3 x + 1}{5 x ^{2} + 1})

What is (\partial)/(\partial x)(sin(2x)cos(2t)) ?
The answer to (\partial)/(\partial x)(sin(2x)cos(2t)) is cos(2t)cos(2x)*2