y^'=((x-3))/((y-4))

Lösung

y^{^{'}} = \frac{( x - 3 )}{( y - 4 )}

y = 4 + x^{2} - 6 x + c_{1} + 16, y = 4 - x^{2} - 6 x + c_{1} + 16

Schritte zur Lösung

y^{'} (x) = \frac{( x - 3 )}{( y - 4 )}

Solve separable ODE:

y = 4 + x^{2} - 6 x + c_{1} + 16, y = 4 - x^{2} - 6 x + c_{1} + 16

y = 4 + x^{2} - 6 x + c_{1} + 16, y = 4 - x^{2} - 6 x + c_{1} + 16

\int x^{2} - x - 2 d x

\frac{d}{d x} (\frac{3 x + 1}{5 x ^{2} + 1})

d er i v a t i v e f (x) = \frac{sin ( x )}{x ^{3}}

x y^{^{'}} + y = 6 x^{2}, y (1) = 2

n \to \infty lim (n^{10})