integral from-2 to 0 of x^2+x-1

Lösung

\int_{- 2}^{0} x^{2} + x - 1 d x

- \frac{4}{3}

Dezimale

- 1.33333 \dots

Schritte zur Lösung

\int_{- 2}^{0} x^{2} + x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} x^{2} d x + \int_{- 2}^{0} x d x - \int_{- 2}^{0} 1 d x

\int_{- 2}^{0} x^{2} d x = \frac{8}{3}

\int_{- 2}^{0} x d x = - 2

\int_{- 2}^{0} 1 d x = 2

= \frac{8}{3} - 2 - 2

Vereinfache

\frac{8}{3} - 2 - 2 : - \frac{4}{3}

= - \frac{4}{3}

x \to 0 lim (\frac{( tan ( 2 x ) )}{x})

d er i v a t i v e 7 x + 1

\frac{d}{d x} (6 arcsinh (tan (x)))

\frac{\partial}{\partial x} (ln (6 x^{2} - 4 y^{2}))

x \to 7 lim (\frac{9 x}{x - 7})