(x^2-x)y^'=y-2xy

Lösung

(x^{2} - x) y^{^{'}} = y - 2 x y

y = \frac{c _{1}}{x ^{2} - x}

Schritte zur Lösung

(x^{2} - x) y^{'} (x) = y - 2 x y

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - x}

y = \frac{c _{1}}{x ^{2} - x}

d er i v a t i v e cos^{4} (θ + 5)

n = 1 \sum \infty \frac{n}{n ^{3} + 1}

d er i v a t i v e (2 x + 3)^{5} + 10 x (2 x + 3)^{4}

s l o p e y = \frac{36 x}{x ^{2} + 36}, (- 3, - \frac{12}{5})

\frac{d}{d x} (lo g_{5} (x e^{x}))