y^'+8y=t+e^{-3t}

Lösung

y^{^{'}} + 8 y = t + e^{- 3 t}

y = \frac{8 t - 1}{64} + \frac{1}{5 e ^{3 t}} + \frac{c _{1}}{e ^{8 t}}

Schritte zur Lösung

y^{'} (t) + 8 y = t + e^{- 3 t}

Solve linear ODE:

y = \frac{8 t - 1}{64} + \frac{1}{5 e ^{3 t}} + \frac{c _{1}}{e ^{8 t}}

y = \frac{8 t - 1}{64} + \frac{1}{5 e ^{3 t}} + \frac{c _{1}}{e ^{8 t}}

\int (8 x^{7} + x^{5}) 6 x^{8} + x^{6} d x

\int \frac{sinh ( x )}{1 - 4 cosh ( x )} d x

x \to 0 lim ((x - 1)^{\frac{1}{2}})

(2 x y^{2} + 3 x^{2} y) d x + (2 x^{2} y + x^{3}) d y = 0

s l o p e (- 5, 3), (5, - 3)