What is the integral from 0 to 1 of 1/(x^{18/19)} ?

The integral from 0 to 1 of 1/(x^{18/19)} is 19

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integral from 0 to 1 of 1/(x^{18/19)}

\int_{0}^{1} \frac{1}{x ^{\frac{18}{19}}} d x

19

Solution steps

\int_{0}^{1} \frac{1}{x ^{\frac{18}{19}}} d x

Apply the Power Rule

: [19 x^{\frac{1}{19}}]_{0}^{1}

= [19 x^{\frac{1}{19}}]_{0}^{1}

Compute the boundaries:

19

= 19

x \to \frac{π}{4} lim (\frac{1 - 2 sin ( 2 x )}{cos ( x ) - sin ( x )})

\frac{d}{d x} (3 x^{2} - 5 x + 7)

\int cos (1 + x) d x

y^{^{''}} + 25 y = cos (8 t)

\frac{d}{d x} (\frac{3 x ^{- 2} + 2}{x ^{2} + 8})

What is the integral from 0 to 1 of 1/(x^{18/19)} ?
The integral from 0 to 1 of 1/(x^{18/19)} is 19