What is the derivative of 3x^2-5x+7 ?

The derivative of 3x^2-5x+7 is 6x-5

What is the first derivative of 3x^2-5x+7 ?

The first derivative of 3x^2-5x+7 is 6x-5

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\frac{d}{d x} (3 x^{2} - 5 x + 7)

6 x - 5

Solution steps

\frac{d}{d x} (3 x^{2} - 5 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (7)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (7) = 0

= 6 x - 5 + 0

Simplify

= 6 x - 5

\int cos (1 + x) d x

y^{^{''}} + 25 y = cos (8 t)

\frac{d}{d x} (\frac{3 x ^{- 2} + 2}{x ^{2} + 8})

\frac{d}{d x} (- \frac{- 2 ln ( x ) + 3}{x ^{3}})

\frac{( 12 s + 3 )}{s ^{2} ( 2 s + 8 )}

What is the derivative of 3x^2-5x+7 ?
The derivative of 3x^2-5x+7 is 6x-5
What is the first derivative of 3x^2-5x+7 ?
The first derivative of 3x^2-5x+7 is 6x-5