What is the limit as x approaches-1 of x/(5sin(x+1)) ?

The limit as x approaches-1 of x/(5sin(x+1)) is diverges

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limit as x approaches-1 of x/(5sin(x+1))

x \to - 1 lim (\frac{x}{5 sin ( x + 1 )})

diverges

Solution steps

x \to - 1 lim (\frac{x}{5 sin ( x + 1 )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x}{5 sin ( x + 1 )}) = - \infty

x \to - 1 - lim (\frac{x}{5 sin ( x + 1 )}) = \infty

= diverges

\frac{d y}{d x}, x - y = x y

\int \frac{x ^{2} + 2}{x} d x

x \to 2 lim (x + 5)

\int_{0}^{1} \frac{1}{x ^{\frac{18}{19}}} d x

x \to \frac{π}{4} lim (\frac{1 - 2 sin ( 2 x )}{cos ( x ) - sin ( x )})

What is the limit as x approaches-1 of x/(5sin(x+1)) ?
The limit as x approaches-1 of x/(5sin(x+1)) is diverges