What is the solution for (dy)/(dx)(2x+y+1)=1 ?

The solution for (dy)/(dx)(2x+y+1)=1 is y=-(\W((c_{1})/(e^{4x+3)}))/2-2x-3/2

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(dy)/(dx)(2x+y+1)=1

\frac{d y}{d x} (2 x + y + 1) = 1

y = - \frac{W ( \frac{c _{1}}{e ^{4 x + 3}} )}{2} - 2 x - \frac{3}{2}

Solution steps

\frac{d y}{d x} (2 x + y + 1) = 1

Solve exact ODE:

y = - \frac{W ( \frac{c _{1}}{e ^{4 x + 3}} )}{2} - 2 x - \frac{3}{2}

y = - \frac{W ( \frac{c _{1}}{e ^{4 x + 3}} )}{2} - 2 x - \frac{3}{2}

\frac{d}{d x} (3 x^{2} + 2 y x)

- 4 x^{2} + 6.25 x + 8, 2.5 x + 7, 0

y = 4, 2 x, \frac{( - 3 x + 7 )}{2}

n = 1 \sum \infty (1 + \frac{k}{n})^{n}

x \to - 8 - lim (\frac{- 5 x + 2}{x + 8})

What is the solution for (dy)/(dx)(2x+y+1)=1 ?
The solution for (dy)/(dx)(2x+y+1)=1 is y=-(\W((c_{1})/(e^{4x+3)}))/2-2x-3/2