What is the derivative of 6sqrt(x)+3\sqrt[3]{x} ?

The derivative of 6sqrt(x)+3\sqrt[3]{x} is 3/(sqrt(x))+1/(x^{2/3)}

What is the first derivative of 6sqrt(x)+3\sqrt[3]{x} ?

The first derivative of 6sqrt(x)+3\sqrt[3]{x} is 3/(sqrt(x))+1/(x^{2/3)}

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derivative of

\frac{3}{x} + \frac{1}{x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (6 x) = \frac{3}{x}

= \frac{3}{x} + \frac{1}{x ^{\frac{2}{3}}}

y = x^{2}, y = 8 x

y^{^{'}} - 6 x^{2} y = 0, y (1) = e

y = \frac{( x + 4 ) ( x ^{2} - 4 x + 16 )}{x ^{3}}

x \to 2 lim (\frac{2}{4 x + 3})

\int \frac{1}{( x - 5 ) ^{2}} - 1 d x

What is the derivative of 6sqrt(x)+3\sqrt[3]{x} ?
The derivative of 6sqrt(x)+3\sqrt[3]{x} is 3/(sqrt(x))+1/(x^{2/3)}
What is the first derivative of 6sqrt(x)+3\sqrt[3]{x} ?
The first derivative of 6sqrt(x)+3\sqrt[3]{x} is 3/(sqrt(x))+1/(x^{2/3)}