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Popular >

area y=x^2,y=sqrt(8x)

Solution

area

y = x^{2}, y = 8 x

Solution

\frac{8}{3}

+1

Decimal Notation

2.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x^{2} - 22 x d x

Solve

\int_{0}^{2} x^{2} - 22 x d x : \frac{8}{3}

The area is:

= \frac{8}{3}

Popular Examples

y^'-6x^2y=0,y(1)=e

y^{^{'}} - 6 x^{2} y = 0, y (1) = e

derivative of y=((x+4)(x^2-4x+16))/(x^3)derivative of

y = \frac{( x + 4 ) ( x ^{2} - 4 x + 16 )}{x ^{3}}

limit as x approaches 2 of 2/(4x+3)

x \to 2 lim (\frac{2}{4 x + 3})

integral of 1/((x-5)^2)-1

\int \frac{1}{( x - 5 ) ^{2}} - 1 d x

derivative of 1/(2sqrt(x))derivative of

\frac{1}{2 x}

Frequently Asked Questions (FAQ)

What is area y=x^2,y=sqrt(8x) ?
The answer to area y=x^2,y=sqrt(8x) is 8/3