What is the derivative of-sin(x-1) ?

The derivative of-sin(x-1) is -cos(x)

What is the first derivative of-sin(x-1) ?

The first derivative of-sin(x-1) is -cos(x)

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\frac{d}{d x} (- sin (x) - 1)

- cos (x)

Solution steps

\frac{d}{d x} (- sin (x) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (sin (x)) - \frac{d}{d x} (1)

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (1) = 0

= - cos (x) - 0

Simplify

= - cos (x)

\frac{\partial}{\partial x} (x ln (x y - 5))

x \to 3 lim (x^{2} + 4)

\int_{- 1}^{1} x (1.5 x^{2}) d x

\frac{d}{d x} (ln (\frac{x + 1}{x - 1}))

\frac{d}{d x} (\frac{4}{( x ^{2} + 9 ) ^{3}})

What is the derivative of-sin(x-1) ?
The derivative of-sin(x-1) is -cos(x)
What is the first derivative of-sin(x-1) ?
The first derivative of-sin(x-1) is -cos(x)