What is the integral from-1 to 1 of x(1.5x^2) ?

The integral from-1 to 1 of x(1.5x^2) is 0

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integral from-1 to 1 of x(1.5x^2)

\int_{- 1}^{1} x (1.5 x^{2}) d x

0

Solution steps

\int_{- 1}^{1} x \cdot 1.5 x^{2} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x 1.5 x^{2} :

Odd

= 0

\frac{d}{d x} (ln (\frac{x + 1}{x - 1}))

\frac{d}{d x} (\frac{4}{( x ^{2} + 9 ) ^{3}})

2 cos (2 t)

f (x) = \frac{x - 1}{x ^{2}}

\int \frac{1}{6 x lo g _{7} ( x )} d x

What is the integral from-1 to 1 of x(1.5x^2) ?
The integral from-1 to 1 of x(1.5x^2) is 0